Question

The present ages of father is 4times the age of his son.After 10 years the age of father will be three times the age of his son.Find their present ages.

Answer 1

Answer:

20 or 0

Step-by-step explanation:

Let son's age be x

Then father's age = 4x

4x:x = 4x/x

After 10 years:

son=x

father=3x

4x+10/x+10=3x/x

Step 1: Cross-multiply.

(4x+10)*(x)=3x*(x+10)

4x²+10x=3x²+30x

Step 2: Subtract 3x^2+30x from both sides.

4x²+10x−(3x²+30x)=3x²+30x−(3x²+30x)

x²−20x=0

x=20 or 0

Son's age=20

Father's age=4(20)=80

Answer 2

Given :

• The present ages of father is 4 times the age of his son.

• After 10 years the age of father will be three times the age of his son.

To find :

• Their present ages =?

Step-by-step explanation :

Let, the present age of the son's be x.

Then, the present age of father's be 4x.

After 10 years son's age = x + 10

After 10 years father's age = 4x + 10

According to the question :

➮ 3(x + 10) = 4x + 10

➮ 3x + 30 = 4x + 10

➮ 3x - 4x = 10 - 30

➮ -1x = - 20

➮ x = 20

Therefore, We got the value of, x = 20 years.

Hence,

The present age of the son's, x = 20 years.

The present age of the father's, 4x = 4 × 20 = 80 years.