Question

The present ages of four persons are in ratio 2:3:4:5. Four years ago, the sum of their ages was 40. Find their present ages. *​

Answer 1

Answer:

8,12,16,20

mark me brainlist

Answer 2

Answer:

Ages of first person, second person, third person and fourth person are 8 years,12 years,16 years and 20 years respectively.

Step-by-step explanation:

Given,present ages of four persons are in ratio 2:3:4:5

Let age of first person be 2x years.

age of second person be 3x years.

age of third person be 4x years and age of fourth person be 5x.

It is also given that four years ago, the sum of their ages was 40.

Before four years,

age of first person

$= (2x - 4) \: years$

age of second person

$= (3x - 4) \: years$

age of third person

$= (4x - 4) \: years$

age of fourth person

$= (5x - 4) \: years$

According to question,

$(2x - 4) + (3x - 4) + (4x - 4) + (5x - 4) = 40$

$14x - 16 = 40 \\ 14x = 40 + 16 \\ 14x = 56 \\ x = \frac{56}{14} \\ x = 4$

Therefore present age of first person

$= (2 \times 4) = 8 \: years$

present age of second person

$= (3 \times 4) = 12 \: years$

present age of third person

$= (4 \times 4) = 16 \: years$

present age of fourth person

$= (5 \times 4) = 20 \: years$

Some more ages related problems:

https://brainly.in/question/11729682

https://brainly.in/question/5403150