Math, asked by annirishigauripurnim, 1 month ago

The present ages of Jai and Preet are in the ratio 5:2. The difference between their ages is 45 years. Find
the sum of their present ages.

Answers

Answered by GauthmathMagnus
0

Answer:

Step-by-step explanation:

Let their ages be 5x and 2x

5x-2x=45

3x=45

x=15

so sum of their ages = 5x+2x=7x=7(15)= 105

Answered by Eutuxia
1

Answer :

  • 35 years.

Given :

  • The ratio of present ages of Jai and Preet = 5:2
  • Difference between their ages = 45 years

To find :

  • the sum of their present ages.

Solution :

⇒ Let's find their present age. Let the ages Jai and Preet be 5x and 2x.

\longrightarrow \sf 5x - 2x = 45

\longrightarrow \sf 3x = 45

\longrightarrow \sf x = \dfrac{45}{3}

\longrightarrow \sf x = \cancel {\dfrac{45}{3} }

\longrightarrow \sf x = 5

\longmapsto \sf Age \: of \: Jai = 5x

\sf = 5 \times 5

\sf = 25 \: years

\sf \longmapsto Age \:  of \: Preet = 2x

\sf = 2 \times 5

\sf = 10 \: years

⇒ Now, let's find the sum.

Sum of their present ages = Age of Jai + Age of Preet

= 25 + 10

= 35 years

  • Therefore, the sum of their present ages is 35 years.

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