Question

The present ages of Meera and her brother are in the ratio 6: 5 Four years ago, the ratio of their ages was 4:3 Find their present ages​

Answer 1

Answer:

Step-by-step explanation:

let present age of meera is  x

and present age of her brother is y

According to the problem,

x/y = 6/5

⇒5x=6y → equation 1

four years ago,the ratio of their ages was 4:3

⇒x-4/y-4 = 4:3

⇒(x-4)3 = (y-4)4

⇒3x-12 = 4y-16

multiply both sides with 3/2

⇒9/2 x - 18 = 6y - 24

⇒9/2 x-18 = 5x - 24

⇒5x - 9/2 x = 24 - 18

⇒x/2 = 6

⇒x=12

∴the present age of meera = 12years

 and present age of her brother =5x=6y

                                                       ⇒5×12 = 6y

                                                        ⇒y=10 years

Hope you understand

Answer 2

Answer:

Let the age of Mira and her brother be x,

then,

Present Age :-

Mina's present age be 6x

and her brother's age be 5x

then,

Four Years Ago Age :-

$6x - 4$

for Mina

$5x - 4$

for her brother

then,

equation will be :-

$\frac{6x - 4}{5x - 4} = \frac{4}{3}$

therefore,

3(6x-4)=4(5x-4)

18x-12=20x-16

18x-20x=12-16

-2x=-4

x=2

Therefore,

Mina's age will be 6x= 6 X 2 = 12

Her brothers age will be 5x= 5 X 2 = 10

Hope fully this will help you!!