The present ages of Meeta and Aarushi are in the ratio 5:4. Eight years from
now, the ratio of their ages will be 6:5. Find their present ages.
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Given :-
- The present ages of Meeta and Aarushi are in the ratio 5:4.
- Eight years from now, the ratio of their ages will be 6:5.
To Find :-
- Their Present Ages
Solution :-
⟼ Let the Present age of Meeta be 5x
⟼ Let the Present age of Aarushi be 4x
After 8 years :
⟼ After 8 years, age of Meeta = 5x + 8
⟼ After 8 years, age of Aarushi = 4x + 8
According to the Question :
➞ 5x + 8 / 4x + 8 = 6/5
➞ 5 (5x + 8) = 6 (4x + 8)
➞ 25x + 40 = 24x + 48
➞ 25x - 24x = 48 - 40
➞ x = 8
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Therefore :
- Present age of Meeta = 5x = 5 × 8 = 40years
- Present age of Aarushi = 4x = 4 × 8 = 36years
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1
Answer:
okay dear no problem please do
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