Question

The present ages of Mohit and Mayank are in the ratio 11:8. After 8 years, the ratio of their age
be 5: 4. Find their present ages.
Total sum of money she has is 7000. The ratio of
she have?​

Answer 1

Step-by-step explanation:

Let Mohit's age be x.

Let Mayank's age be y.

ATQ,

x/y = 11/8

8x = 11y

8x-11y = 0                --(1)

Case 2,

x+8/y+8 = 5/4

4x+32 = 5y+40

4x-5y = 8                 --(2)

Multiply (2) by 2

8x-10y = 16

-8x+11y = 0

__________

      y = 16

Put y in (1)

8x-176 = 0

x = 176/8

x = 22

their ages are 22 and 16.

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