Math, asked by Raunitraj11, 1 year ago

The present ages of pawan and kalyan are in the ratio of 4:5. The product of their ages numerically is equal to 980. Find the difeerence between their ages (in years)

Answers

Answered by Panzer786
5
Heya !!



Let the present ages of pawan and kalyan be 4x and 5x years.






A/Q




4X × 5X = 980




20X² = 980




X² = 980/20



X² = 49




X = √49 = 7




Present age of pawan = 4X = 4 × 7 = 28 years.



And,


Present age of kalyan = 5X = 5 × 7 = 35 years.



Difference between their ages = 35 - 28 = 7 years.
Answered by ShadowplayerLC
5

RATIO OF AGES = 4:5

LET PAWAN AGE = 4X

KALYAN'S AGE = 5X

PRODUCT OF AGES = 980

4X*5X = 980

20X^2 = 980

X^2 = 980/20

X^2 = 49

X = 7

THERE FORE THEIR AGES ARE 4X = 28YRS AND 5X = 35 YRS RESPECTIVELY

DIFFERENCE OF AGES = 35-28 = 7 YEARS

THANK YOU .............

Similar questions