The present ages of pawan and kalyan are in the ratio of 4:5. The product of their ages numerically is equal to 980. Find the difeerence between their ages (in years)
Answers
Answered by
5
Heya !!
Let the present ages of pawan and kalyan be 4x and 5x years.
A/Q
4X × 5X = 980
20X² = 980
X² = 980/20
X² = 49
X = √49 = 7
Present age of pawan = 4X = 4 × 7 = 28 years.
And,
Present age of kalyan = 5X = 5 × 7 = 35 years.
Difference between their ages = 35 - 28 = 7 years.
Let the present ages of pawan and kalyan be 4x and 5x years.
A/Q
4X × 5X = 980
20X² = 980
X² = 980/20
X² = 49
X = √49 = 7
Present age of pawan = 4X = 4 × 7 = 28 years.
And,
Present age of kalyan = 5X = 5 × 7 = 35 years.
Difference between their ages = 35 - 28 = 7 years.
Answered by
5
RATIO OF AGES = 4:5
LET PAWAN AGE = 4X
KALYAN'S AGE = 5X
PRODUCT OF AGES = 980
4X*5X = 980
20X^2 = 980
X^2 = 980/20
X^2 = 49
X = 7
THERE FORE THEIR AGES ARE 4X = 28YRS AND 5X = 35 YRS RESPECTIVELY
DIFFERENCE OF AGES = 35-28 = 7 YEARS
THANK YOU .............
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