Math, asked by kumaraaditya442, 7 months ago

The present ages of Ram and Mohan are in the ratio 11:8 . Eight years later

the sum of their ages will be 54 years . What are their present ages?​

Answers

Answered by Anonymous
21

Answer:

Ten years ago, P was half of Q's age. If the ratio of their present ages is 3:4 3 : 4 , what will be the total of their present ages? A. 45 45, B. 30 ...

Answered by SANDHIVA1974
1

Given :

The present ages of Rohit and Mayank are in the ratio 11 : 8 .

8 years later the sum of their ages will be 54 years.

To Find :

Present Age of Rohit and Mayank .

Solution :

\longmapsto\tt{Let\:Present\:age\:of\:Rohit\:be=11x}

\longmapsto\tt{Let\:Present\:age\:of\:Mayank\:be=8x}

After 8 years :

\longmapsto\tt{Age\:of\:Rohit=11x+8}

\longmapsto\tt{Age\:of\:Rohit=8x+8}

A.T.Q :

\longmapsto\tt{11x+8+8x+8=54}

\longmapsto\tt{19x+16=54}

\longmapsto\tt{19x=54-16}

\longmapsto\tt{19x=38}

\longmapsto\tt{x=\cancel\dfrac{38}{19}}

\longmapsto\tt\bf{x=2}

Value of x is 2 .

Therefore :

\longmapsto\tt{Present\:Age\:of\:Rohit=11(2)}

\longmapsto\tt\bf{22\:yrs}

\longmapsto\tt{Present\:Age\:of\:Mayank=8(2)}

\longmapsto\tt\bf{16\:yrs}

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