Math, asked by kardileswara10, 4 days ago

The present ages of Ravi and Raj are 16 years and 12 years respectively. How many years ago would the ratio of their ages be 5:3 ?​

Answers

Answered by vishwa11747
1

Answer:

Let their present age be 4a and 5a.

After 8 years, their ages will be (4a+8) and (5a+8)

Ratio would be (4a+8) : (5a+8)

But this ratio is given to be 5:6. Therefore

(4a+8) : (5a+8) = 5:6

solve this (4a+8) / (5a+8) = 5/6

=> 6 x (4a+8) = (5a+8) x 5

=> 24a + 48 = 25a + 40

=> a = 8

So their present age would be

4a = 4x8 = 32

5a = 5x8 = 40

Step-by-step explanation:

Answered by devindersaroha43
0

Answer: Let their present age be 4a and 5a.

After 8 years, their ages will be (4a+8) and (5a+8)

Ratio would be (4a+8) : (5a+8)

But this ratio is given to be 5:6. Therefore

(4a+8) : (5a+8) = 5:6

solve this (4a+8) / (5a+8) = 5/6

=> 6 x (4a+8) = (5a+8) x 5

=> 24a + 48 = 25a + 40

=> a = 8

So their present age would be

4a = 4x8 = 32

5a = 5x8 = 40

Step-by-step explanation:

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