the present ages of reenu and Rohit are in the ratio of 3:5 after 10 years their ages will be 5:7. Find their present ages. with steps too please
Answers
Given: The present ages of Reenu and Rohit are in the ratio of 3 : 5. & After 10 years their ages will be 5 : 7 respectively.
Need to find: Their present ages?
⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
❍ Let's say, that the present age of Reenu be 3x and present age of Rohit be 5x respectively.
⠀
⠀⠀
- After ten years, the age of Rohit and Reenu will be 5 : 7
☆ After 10 years, their ages —
- Reenu's age = (3x + 10) years
- Rohit's age = (5x + 10) years
⠀
Therefore,
⠀
⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
⠀⠀⠀
⠀⠀⠀⠀
- Reenu's present age, 3x = 3(5) = 15
- & Rohit's present age, 5x = 5(5) = 25
⠀
⠀⠀⠀⠀⠀
Given :-
the present ages of Reenu and Rohit are in the ratio of 3:5 after 10 years their ages will be 5:7.
To Find :-
Present ages
Solution :-
Let the present age of Reenu be 3a
Present age of Rohit be 5a
After 10 years
Present age of Reenu = 3a + 10
Present age of Rohit = 5a + 10
3a + 10/5a + 10 = 5/7
7(3a + 10) = 5(5a + 10)
21a + 70 = 25a + 50
70 - 50 = 25a - 21a
20 = 4a
20/4 = a
5 = a
Therefore
Present age of Reenu = 3a = 3(5) = 15 years
Present age of Rohit = 5a = 5(5) = 25 years