Math, asked by harrisonshika12, 10 days ago

the present ages of reenu and Rohit are in the ratio of 3:5 after 10 years their ages will be 5:7. Find their present ages. with steps too please​

Answers

Answered by WilsonChong
0

Answer:

Present age of reenu and Rohit are 15 and 25 respectively.

Step-by-step explanation:

Please refer to the attachment for explanation. The key to solving this problem is to frame the worded question in algebraic equations and solve it from there.

Attachments:
Answered by harshit5645
2

Answer:

\huge\bigstar\green{QUESTION:}

➡the present ages of reenu and Rohit are in the ratio of 3:5 after 10 years their ages will be 5:7. Find their present ages. with steps too please

\huge\bigstar\red{ANSWER:-}

➡Given the ratio of present ages of Sonal and Manoj=7:5

Let the age of Sonal be 7x years and age of Manoj be 5x years

10 years later their age will (7x+10) and (5x+10)

Given ratio of ages after 10 years=9:7

So now assume the ages be 9x and 7x

∴7x+10+5x+10=9x+7x

9x−5x=20

4x=20

x=5

So, the present age of Sonal=7x=7×5=35years

and the present age of Sonal=5x=5×5=25years

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