Question

the present ages of reenu and Rohit are in the ratio of 3:5 after 10 years their ages will be 5:7. Find their present ages. with steps too please​

Answer 1

Answer:

${\huge{\pink{↬}}} \: \: {\huge{\underline{\boxed{\bf{\pink{Answer}}}}}}$

The ratio of Hari's and Harry's present ages is 5:7 

So, let their ages be 5x and 7x

After 4 years their ages will be in ratio 3:4

Therefore,(5x+4)/(7x+4)=3/4

or, 4(5x+4)=3(7x+4)

or, 20x+16=21x+12

or, 16−12=21x−20x

or, 4=1x

or, x=4

Therefore, present age of Hari = 5x=(5×4)=20 years.

Present age of Harry =7x=(7×4)=28 years

The sum of their age is 28+20=48years

Answer 2

$\huge \rm {\underline{Answer:-}}$

The ratio of Hari's and Harry's present ages is 5:7

So, let their ages be 5x and 7x

After 4 years their ages will be in ratio 3:4

Therefore,(5x+4)/(7x+4)=3/4

or, 4(5x+4)=3(7x+4)

or, 20x+16=21x+12

or, 16−12=21x−20x

or, 4=1x

or, x=4

Therefore, present age of Hari = 5x=(5×4)=20 years.

Present age of Harry =7x=(7×4)=28 years

The sum of their age is 28+20=48years