Math, asked by Akshaykanojiy1495, 10 months ago

The present ages of roy and michael are in the ratio 5:65:65, colon, 6. 888 years from now, their ages will be in the ratio 9:109:109, colon, 10. What is the present age of roy?

Answers

Answered by TheGrandmaster47
0

Step-by-step explanation:

5:6 is the ratio of present ages

9:10 is the ratio of their ages after 8 years

Therefore we can say that,

5x+8/6x+8 = 9/10

Now we have to cross-multiply

\frac{5x+8}{6x+8} = \frac{9}{10} \\

10(5x+8) = 9(6x+8)

50x + 80 = 54x + 72

Now we separate variables from constants

--> 80-72 = 54x - 50x

--> 8 = 4x

Therefore x = 8/4

x = 2

So, the Present age of Roy = 5x = 5*2 = 10 years

      the present age of Michael = 6x = 6*2 = 12 years

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