Question

The present ages of sheela &
Sunitha are in the ratio 5:4
Eight years from now, their ages
will be in the ratio 6:5. find their
present ages....????​

Answer 1

Step-by-step explanation:

let their ages be 5x and 4x

8 years ago

let their ages be 6x and 5x

ATQ

5x +8 = 6x

8=6x -5x

x = 8

age of sheela 8*5=40

age of sunita 8*4=32

Answer 2

$\bf{\large{\underline{\underline{Answer:-}}}}$

Present ages of Sheela and Sunitha are 40 years and 32 years respectively.

$\bf{\large{\underline{\underline{Explanation:-}}}}$

Given :-

Ratio of present ages of Sheela and Sunitha = 5 : 4

Ratio of ages of Sheela and Sunitha after 8 years = 6 : 5

To find :- Present ages

Solution :-

Ratio of present ages of Sheela and Sunitha = 5 : 4

Consider present age Sheela and Sunitha as 5x and 4x respectively

After 8 years :-

Sheela's Age = (5x + 8)

Sunitha's age = (4x + 8)

Ratio of ages of Sheela and Sunitha after 8 years = 6 : 5

According to the question :-

Equation formed :-

$\boxed{\tt{ \dfrac{5x + 8}{4x + 8} = \dfrac{6}{5} }}$

By Cross multiplication :-

$\tt{(5x + 8)5=6(4x + 8)}$

$\tt{25x + 40 = 24x + 48}$

$\tt{25x - 24x = 48 - 40}$

$\tt{x = 8}$

Now we can find the present ages of Sheela and Sunitha

Sheela's present age = 5x = 5(8) = 40 years

Sunitha's present age = 4x = 4(8) = 32 years

$\bf{\large{\underline{\underline{Verification:-}}}}$

To know whether the answer is correct or not substitute present ages of Sheela and Sunitha in the equation that is formed to solve.

$\tt{ \dfrac{40 + 8}{32 + 8} = \dfrac{6}{5} }$

$\tt{ \dfrac{48}{40} = \dfrac{6}{5} }$

$\tt{ \dfrac{6}{5} = \dfrac{6}{5} }$

Therefore the present ages of Sheela and Sunitha are 40 years and 32 years respectively.