Math, asked by sinhaharshit7201, 6 months ago

The present ages of Sonu and Monu are in the ratio 4
7. 10 years ago, the age of Monu was twice the age
of Sonu. Find the present age of Sonu (in years).​

Answers

Answered by GeetanVerma
2

Let Sonu's age = 4x

Monu's age = 7x

ATQ

7x - 10 = 2(4x - 10)

7x - 10 = 8x - 20

20 - 10 = 8x - 7x

x = 10

Sonu's age = 4 × 10

= 40 years

Monu's age = 7 ×10

= 70 years

Answered by wwwjeevanraj09
2

Step-by-step explanation:

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