The present ages of the father and the sons are in the ratio 7:3 .Tens years ago,the father's age was four times of his son. Find their present ages.
plz help me.
Answers
Answered by
1
Answer:
The Father's age is 42 years and the Son's age is 18years
Step-by-step explanation:
Since the present ages are in ratio 7:3
Therefore,
take father's age as 7x
take Sons age as 3x
∴(x-10)=4(3x-10) [10 years ago]
= 7x-10=12x-40
= 7x-12x= -40+10
= -5x= -30
= x=6
∴ Fathers age = 7*6 = 42 years
Sons age = 3*6 = 18 years
VERIFICATION:
42/18=7/3
⇒Hence Proved
Similar questions