Math, asked by Ammu19112001, 7 months ago

The present ages of three brothers are in the proportion 12:14:17. The difference between

the ages of the elder and the eldest is 6 years. What will be the proportion of their ages after

four years?​

Answers

Answered by jeannvilladolid
1

Answer:

your question is kinda confusing

Answered by Zhaoyiqinn31
5

Answer:

Let the common value of their age be 'X'

Then proportion become 12x:14x:17x

According according to problem,

Elder brother age is 14x

Eldest brother age is 17x

17x - 14x = 6

: 3x = 6

: x = 6/3

: x = 2

Thus the present age of

youngest brother is : 12x

: 12*2

present age : 24 years

elder brother is : 14x

: 14*2

present age : 28 years

eldest brother is : 17x

: 17*2

: 34 years

After 4 year the age of

youngest brother is 28 years

elder brother is 32 years

eldest brother is 38 years

Thus the proportion becomes.

28 : 32 :38

which can be simplified and writen as.

14 : 16 : 19

hope it is helpful for you and make this answer as brainliest.

Thank you.

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