The present ages of three persons are in proportions 4:7:9. eight years ago, the sum of their ages was 56. find their present ages.
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Let present ages be 4x,7x,and 9x
Eight yrs ago their ages were (4x-8),
(7x-8)and (9x-8).
Sum of their ages 8yrs ago
=4x+7x+9x-24=56
=>20x=80
=>x=4.
Their present ages are 16,28,36
Hope it helps
Eight yrs ago their ages were (4x-8),
(7x-8)and (9x-8).
Sum of their ages 8yrs ago
=4x+7x+9x-24=56
=>20x=80
=>x=4.
Their present ages are 16,28,36
Hope it helps
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