The present ages of three persons are in proportions 4:7:9.8 yrs ago the sum of their ages wass 56.Find the present ages
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Answer:
The ages are 8,14,18,16
Step-by-step explanation:
The sum is 56
Let the ages be 4x,7x,9x,8x,
According to the question
4x+7x+9x+8x=56
Therefore , 28x=56
Therefore x=56/28
Therefore x=2
Therefore the ages are 8,14,18,16
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