Question

The present ages of three persons in proportions 4:7:9. Eight years ago, the
sum of their ages was 56. Find their present ages (in years)
​

Answer 1

Answer:

let the present ages of the 3 persons be as = 'x'

the age of 1st person= 4x

the age of 2nd person= 7x

the age of 3rd person = 9x

the sum their ages after 8 years will be = 56

: . after 8 years their ages will be= 4x+8,7x+8 and 9x+8

so their present ages will be = 4x+8 + 7x+8 + 9x+8 = 56.

=/4x+7x+9x+8+8+8=56

=/20x+24=56

=/20x=56-24

= so x is = 32/20

=/ x=8

Step-by-step explanation: