The present ages of three persons in proportions 4:7:9. Eight years ago, the
sum of their ages was 56. Find their present ages (in years)
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let the present ages of the 3 persons be as = 'x'
the age of 1st person= 4x
the age of 2nd person= 7x
the age of 3rd person = 9x
the sum their ages after 8 years will be = 56
: . after 8 years their ages will be= 4x+8,7x+8 and 9x+8
so their present ages will be = 4x+8 + 7x+8 + 9x+8 = 56.
=/4x+7x+9x+8+8+8=56
=/20x+24=56
=/20x=56-24
= so x is = 32/20
=/ x=8
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