Question

The present ages of three persons in proportions 4:7:9.Eight year ago, the sum of their ages was 56. find their present ages (in years)

Answer 1

here is your Answer!!

let the age be 4x , 7x ,9x

then eight years ago
so


4x-8,

7x-8

9x-8

now the sum of the age = 56

➡ 4x-8+7x-8+9x-8 = 56

➡ 20x -24 = 56

➡ 20x = 56+24

➡ X = 80/20

➡ X = 4

so the present age will be

4×4 = 16 years
7×4 = 28 years
9×4 = 36 years

hope it's helpful ✌✌