Question

The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
A.46985
B.16, 28, 36
C.20, 35, 45
D.None of these

Answer 1

hey!

let the meet of ratio of ages be x.

Then age of three persons = 4x, 7x and 9x.

Since sum of their ages before, 8 years = 56

=) (4x-8) + (7x-8) + (9x-8) = 56

=) 4x + 7x + 9x - 24 = 56

=) 20x = 80

=) x = 80/20 = 4

Hence present ages = 4*4, 7*4 and 9*4.

= 16,28,36.

hope it helps you!!

Answer 2

$\huge{Hey,\:Mate\: Here\: Is\:your\:Answer}$

$\textbf{Given That ....}$

The Present Age OF Three Persons Are In Ratio of 4:7:9 , And It's Also Said That 8 Years Ago The Sum Of

Their Ages was 56. Now We Need To Find Their Present Age ....

So let's Move To Solution ...

$\textbf{Solution ...}$

According To Question It's Said That The Present Ages Of Three Persons Are In Ratio of 4:7:9

[teSo Let 'x' Be The Constant Of Ratio..

So The Age Of

$\textbf{First Person = 4x}$

$\textbf{Second Person = 7x}$

$\textbf{Third Person = 9x}$

So Now 8 years Ago Their Ages =

$\textbf{First Person = 4x-8}$

$\textbf{Second Person = 7x-8}$

$\textbf{Third Person = 9x-8}$

So According To Question It's Said That Sum Of Their Age's 8years Ago Is Equal To 56 .

So By This We Have...

$(4x - 8) + (7x - 8) + (9x - 8) = 56$

Now Opening Brackets And Finding Sum Of LHS We Have ...

$20x - 24 = 56$

Now Taking - 24 To RHS We Have ....

$20x = 80$

Now Taking 20 To RHS We Have....

$x = 4$

So Now We Have Value Of 'X' Equal To 4

Now Putting This Value In Their Present Ages We Have...

$\textbf{First Person = 4x = 4\times4 = 16years }$

$\textbf{Second Person = 7x = 7\times4 = 28years }$

$\textbf{Third Person = 9x =9\times4=36years }$

Hence The Required Answer Is ---

$\boxed{16,28,36 years}$