Question

The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years). ? Ans

Answer 1

Answer:

16 , 28 , 36

Step-by-step explanation:

let present age of first person be 4x

let present age of second person be 7x

let present age of third person be 9x

eight years ago sum of their ages was 56 ,

∴ (4x-8) + (7x-8) + (9x-8) = 56

4x-8+7x-8+9x-8=56

20x-24=56

20x=56+24

20x=80

x= 80/20

x= 4

therefore present age of first person = 4x= 4*4= 16

present age of second person = 7x=7*4=28

present age of third person = 9x = 9*4 = 36