Math, asked by nishathomas045, 6 months ago

The present ages of two children are in the ratio 2:3. Five years ago, the ratio of their ages was 1:2. Find their present ages.​

Answers

Answered by sarwerhussain1786
0

Step-by-step explanation:

let the children age be x

2x - 5 / 3x - 5 = 1/2

x = 5

the age of first sons is 10. yr

the age of second sons is 15yr

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Answered by gitanjali4922
9

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  • Ratio of present ages of two children is 2 : 3
  • Five years ago, the ratio of their ages was 1 : 2.

________________________

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  • Their present ages.

_________________________

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Let ,

\color{black}\bold</p><p>{the \: present \: age \: of \:  {1}^{st} \:child \: be\:2x}

\color{black}\bold</p><p>{the \: present \:age \: of \:  {2}^{nd} \:child \: be \: 3x}

Then,

\color{black}\bold</p><p>{the \: age \: of \:  {1}^{st}child \: before\: 5\: year}\color{black}\bold{= 2x-5}

\color{black}\bold</p><p>{the \: age \: of \: {2}^{nd} child \: before\:5 \: year}\color{black}\bold{= 3x-5}

\color{black}\bold</p><p>{A/q \: \: \frac{2x - 5}{3x - 5} =  \frac{1}{2}  }

\color{black}\bold</p><p>{ \implies \: 4x - 10 = 3x - 5}

\color{black}\bold</p><p>{ \implies4x - 3x =  - 5 + 10}

\color{black}\bold</p><p>{ \implies \: x = 5}

{ \boxed{∵x = 5}}</p><p>

\color{black}\bold</p><p>{By \: putting \: the \: value \: of \: x}

\color{black}\bold</p><p>{the \: present \: age \: of \:  {1}^{st}\:child  } \\ \color{black}\bold</p><p>{ = 2x = (2 \times 5 )= 10 \: years}

\color{black}\bold</p><p>{the \: present \: age \: of \:  {2}^{nd}\:child } \\ \color{black}\bold</p><p>{ = 3x =( 3 \times 5) = 15 \: years}

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