Question

the present ages of two students are in the ratio 5 : 3 . after 6 year, their ages will be in the ratio 7 : 5. the present age of the first student is

Answer 1

Answer:

Answer: The answer is 24 years.

Answer 2

Step-by-step explanation:

let's take the two students as a and b.

let's take the common multiple as x.

the age of student a = 5x.

the age of student b = 3x.

after 6 years, their ages will be -

the age of student a = 7x.

the age of student b = 5x.

the age of student a = 5x + 6

the age of student b = 3x + 6

so, 5x + 6+ 3x + 6 = 7x + 5x.

8x + 12 = 12x

12 = 12x-8x

12 = 4x

12/4 = x

3 = x.

so x is equals to 3.

therefore,

present age of student a = 5x = 5 × 3 = 15

present age of students b = 3x = 3 × 3 = 9.

hope it may help you.