The present ages of two students are in the ratio 5: 3. After 6 years, their ages
be in the ratio 7:5. The present age of the first student is
(c) 20 years
(d) 15 years
(a) 5 years
(6) 10 years
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Answer:
c) 20 years
Step-by-step explanation:
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let the present age of first student be x years and second student be y years
by the first given condition,
x/y=5/3
3x=5y
3x-5y=0----(1)
by the second given condition,
x+6/y+6=7/5
5(x+6)=7(y+6)
5x+30=7y+42
5x-7y=42-30
5x-7y=12---(2)
multiply eqn 1 by 7 & eqn 2 by 5
21x-35y=0----(3)
25x-35y=60----(4)
substract eqn 3 from 4
25x-35y =60
-
21x-35y=0
------------------------
4x=60
x=60/4
x=15
hence the present age of first student is 15 years
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