Math, asked by manoj579, 10 months ago

The present average age of a man and his twin sons is 30 years. The ratio of the ages of the man and one of his sons is 5:2 . present age of the man is

(a) 42 yrs (b) 45 (c) 60 (d) 50


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Answers

Answered by tiyadubeylko
67

Heya mate,,

her is ur answr

age of man is 50

Step by step explanation

since there are three members father and twin sons

so total age of the three peoples = 3*30=90

(marking this equatn as no. 1)

the ratio if the ages of twin sons is 5:2:2

assuming the ratios of father be 5x and his two sons be 2x :2x now total sum of their ages is 5x+2x+2x= 9x

(marking this equatn as no. 2)

so equating 1 & 2

we get

90 = 9x

from here we will get

x= 10

putting value of x in father's age ratio = 5x = 5*10= 50years

hope it helps

plss mark as brainliest


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Answered by Anonymous
98

Answer:-

Option (d) 50 years

Present ages of the man = 50 years.

Explanation:-

Average age of man and his twin sons = 30

Ratio of father and one son = 5 : 2

Therefore we can take their ages  as  x  

Total age of three  = 30 x 3 = 90 yr

Ratio of father and one son = 5 : 2

Ratio of father and both the sons = 5 : 2 : 2

⇒ 5x + 2x +2x = 90  

⇒ 9x = 90

⇒ x = 10

Present age of the man = 5 × 10 = 50 years.

Present age of the sons = 2 × 10 = 20 years (both sons)


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