Question

. The present of Sita’s father is three times the present age

of Sita. After six years sum of their ages will be 69 years. Find

their present ages.​

Answer 1

GIVEN:

The present age of Sita's father is three times the present age.

After six years sum of their ages will be 69.

TO FIND:

Their present ages

SOLUTION:

Let the Sita's age be 'x' and her father's age be '3x'.

After six years, sum of their ages will be 69.

(x + 6) + (3x + 6) = 69

==> 4x + 12 = 69

==> 4x = 69 - 12

==> 4x = 57

==> x = 57/4

==> x = 14 years 3 months.

3x = 14.25 × 3 = 42. 75 = 42 years 9 months.

Therefore, their present ages are 14 years 3 months and 42 years 9 months.

Answer 2

$\bold\red{\underline{\underline{Answer:}}}$

$\green{\underline{\underline{Solution:}}}$

$\red{Let \ the \ present \ ages \ of \ Sita}$

$\red{and \ her \ father \ be \ x \ and \ y}$

$\red{years \ respectively}$

$\bold\green{According \ to \ first \ condition}$

Thepresent age of Sita's father is three times her age.-----(Given)

$\bold{y=3x....(1)}$

After six years their ages will be x+6 and y+6 years.

$\bold\green{According \ to \ second \ condition}$

Sum of age of Sita and her father will be 69 years.-----(Given)

$\bold{x+6+y+6=69}$

$\bold{x+y+12=69}$

$\bold{x+y=69-12}$

$\bold{x+y=57....(2)}$

Substituting equation(1) in equation(2)

$\bold{x+ 3x=57}$

$\bold{4x=57}$

$\bold{x=14.25 \ years}$

$\bold{i.e. \ x=14 \ years \ and \ 3 \ months}$

Substituting value of x in equation(1)

$\bold{y=3(14.25)}$

$\bold{y=42.75 \ years}$

$\bold{i.e. \ y=42 \ years \ and \ 9 \ months}$

$\bold\red{Therefore \ present \ ages \ of \ Sita}$

$\bold\red{and \ her \ father \ is \ 14 \ years \ and \ 3 \ months}$

$\bold\red{and \ 42 \ years \ and \ 9 \ months \ respectively.}$