The present population of a city is 12,00,000. If it increases at the rate of 8% every year,
then the population of the city after 2 years is
(a) 199680
(b) 1399680
(C) 1500000 (d) 1299680
Answers
Answered by
3
Answer:
b) 1399680
Step-by-step explanation:
Total increase in percent = x+y+xy/100
= 8+8+64/100 = 16.64%
Increase in population = 16.64/100* 1200000 = 199680
Total population
after 2 years = 1200000+199680 = 1399680
Answered by
8
Answer:
b) 1399680
Step-by-step explanation:
Population of 1st year = 12,00,000 + (8%×12,00,000)
=> 1200000 + 96000 = 12,96,000
Population of 2nd year= 12,96,000 + (8% × 12,96,000)
=> 12,96,000 + 1,03,680 = 13,99,680
Total population in 2 years = 1399680
PLZ MARK THE BRAINLIEST !!!!!
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