THE PRESENT POPULATION OF A CITY IS 18522000. IF IT HAS BEEN INCREASED AT THE RATE OF 5% PA FIND THE INCREASE IN NUMBER PEARS AGE OF POPULATION FROM THE POPULATION 3 Y
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here the increase in population after every year is 5%
Today's after 2 years will be20420505
Today's after 2 years will be20420505
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p=18522000
r=5%pa
t=3year
a=p(1+r/100)^t
a=18522000(1+5/100)^3
a=18522000(1+1/20)^3
a=18522000×21/20×21/20×21/20
a=(18522×21×21×21)8
a=21441560.25people
18522000×5/100×3
185220×5×3
926100×3
2778300
18522000+2778300
21300300people
r=5%pa
t=3year
a=p(1+r/100)^t
a=18522000(1+5/100)^3
a=18522000(1+1/20)^3
a=18522000×21/20×21/20×21/20
a=(18522×21×21×21)8
a=21441560.25people
18522000×5/100×3
185220×5×3
926100×3
2778300
18522000+2778300
21300300people
sonukumar985:
(18522×21×21×21)/8=21441530.25people
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