Question

The present population of a city is 2,50,000. The rate of increase of population is 6% p.a. What will be the
population of the city after 2 years?​

Answer 1

Answer:

2,80,900

Step-by-step explanation:

Present population (P) = 2,50,000

Rate of increase (R) = 6%

Number of years (n) = 2 years

A = P (1 + R/100)ⁿ

=> A = 2,50,000 (1 + 6/100)²

=> A = 2,50,000 (53/50) (53/50)

=> A = 2,80,900

Hence, the population after 2 years will be 2,80,900.

Answer 2

Answer:

280900

Step-by-step explanation:

Present population=2,50,000

Rate(increase)=6%p.a.

Population after 2years=?

-- population after 1year =present population+increased population=250000+250000*6/100

=250000+15000

=265000

population after 2years=population of 1st year+increased population

=265000+265000*6/100

=265000+15900

=280900

the population of the city after 2years will be 280900.