Question

The present population of a city is 3,02,500. if the population increases by 10% every year, what was the population of the city two year ago ?

Please solve​

Answer 1

Answer:

Let the population before two years ago be x

Given the population increases by 10%

So increase in population after one year is

100/10 * x=0.1x

So population after one year is x+0.1x=1.1x

Increase in population after another one year is

100/10 * 1.1x=0.11x

So population at present is 1.1x+0.11x=1.21x

But given population at present is 3,02,500

⟹1.21x=302500

⟹x= 1.21=302500

=2,50,000

Population of city two years ago is 2,50,000

Answer 2

Answer:

250000

Step-by-step explanation:

Effective rate in 2 years = 10 + 10 + 10×10/100 = 21%

Thus it's will increase by 21 % in two years time

X * (1 + 21/100) = 302500

X = 302500*100/121 = 250000