Question

The present population of a state is 9765625 . If rate growth is 4% p.a find increased population after 2 years

Answer 1

$\bf\huge\underline{Answer :-}$

$\large{\boxed{\underline{\sf Population \: after \: 2 \: years \: = 10562500 }}}$

$\bf\huge\underline{Solution :-}$

Given,

• Present population = 9765625

• Rate of increase = 4 %

• Time = 2 years

According to question,

$\sf\longrightarrow P (1 + \dfrac{R}{100})^(n)$

$\sf\longrightarrow 9765625 (1 + \dfrac{4}{100})^(2)$

$\sf\longrightarrow 9765625 (\dfrac{100 + 4}{100})^(2)$

$\sf\longrightarrow 9765625 (\dfrac{104}{100})^(2)$

$\sf\longrightarrow 9765625 \times \dfrac{104}{100} \times \dfrac{104}{100}$

$\huge\sf\therefore 10562500$

Hence, the population after 2 years will be 10562500 respectively.

Answer 2

Answer:

• 10,562,500 population increased after 2 years.

Given :

• Principle = 9765625

• Rate = 4%

• Time = 2 years

To find :

• The population after 2 years =?

Step-by-step explanation:

Increased Population after two years = p(1+r/100)^n

Substituting the values in the above formula, we get,

➟ 9765625(1 + 4/100)²

➟ 9765625(104/100)²

➟ 9765625(26/25)²

➟ 9765625 x 26/25 x 26/25

➟ 15,625 x 26 x 26

➟ 10,562,500

Thus, 10,562,500 population increased after 2 years.