Question

The present population of a town in 2,00,000. Its population increases by 10% in the first year and 15% in the second year. Find the population of the town at the end of two years.

Answer 1

Present population = 200000

R1 = 10%

R2 = 15%

Population after 2 years is:

$P_2 =P \bigg(1 + \frac{R_1}{100} \bigg) \bigg(1 + \frac{R_2}{100} \bigg)\\ \\ P_2 =200000\bigg(1 + \frac{10}{100} \bigg) \bigg(1 + \frac{15}{100} \bigg)\\ \\ P_2 =200000\big(1 + 0.1 \big) \big(1 + 0.15 \big)\\ \\ P_2 =200000 \times \big(1.1 \big) \times \big(1.15 \big)\\ \\ P_2 = 253000$


Population after 2 years is 253000

Answer 2

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Present population = 200000

R1 = 10%

R2 = 15%

Population after 2 years is:

$P_2 =P \bigg(1 + \frac{R_1}{100} \bigg) \bigg(1 + \frac{R_2}{100} \bigg)\\ \\ P_2 =200000\bigg(1 + \frac{10}{100} \bigg) \bigg(1 + \frac{15}{100} \bigg)\\ \\ P_2 =200000\big(1 + 0.1 \big) \big(1 + 0.15 \big)\\ \\ P_2 =200000 \times \big(1.1 \big) \times \big(1.15 \big)\\ \\ P_2 = 253000$

Population after 2 years is 253000

HOPE SO IT WILL HELP.....