Question

The present population of a town is 10000 and was 8000 two years ago if it grows at the same rate what will be the population two years hence

Answer 1

Let x be the rate at which population grows

=> before one year , population = 8000 + x% of 8000 = (8000 + 80x) = y

Present population = y + x % of y

=> 10000= 8000 + (80x) + 0.8x^2 + 80x

solving for x, x = 11.8

So after two years, population will be

10000 + 1180 + 11.8(10000+1180)/100

= 12500

hope it would be helpful

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