Math, asked by bhavi2022, 3 days ago

The present population of a town is 108000.
The population increased by 66 2
3
% during first
year and decreased by 16 2
3
% second year.
During third year is increased by 33 1
3
%. Find
the population of the town after 3 years.

Answers

Answered by sakshisharma2718
2

Step-by-step explanation:

persent population= 1080000

first year population= 108000× 200/3×1/100

=72000

increased population=108000+72000=180000

second year= 1/6 × 180000=30000

decreased population= 180000-30000=150000

third year population=150000×1/3=50000

increased population= 150000+50000= 200000answer

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