the present population of a town is 12500 and it increasing at a rate 8% per annum what will be the population of town after 2 years
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Answer:
solution :-
A =(100+R/100) power n
so
P =12500
R =8%
T = 2
SO
12500 × (108/100) POWER2
12500 ×108/100 ×108/100
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12500 is the population
Increased 8% per year
Population after 2 years will be
12580
Increased 8% per year
Population after 2 years will be
12580
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