Math, asked by theenadurairaj, 3 months ago

The present population of a town is 15,000. If the population increases at the rate of

4% per year, then find the population after one year​

Answers

Answered by haribunnyfan
0

Answer:

15600

Step-by-step explanation:

after one year=104/100×15000=15600

Answered by IntrovertLeo
11

Given:

A town with

  • Population = 1500
  • Rate = 4%
  • Time = 1 year

What To Find:

We have to find the population of the town after one year.

How To Find:

To find the population of the town, we have to

  • Use the formula.
  • Substitute the value.
  • Solve to find the population.

Formula:

\sf Total \: Population = Present \: Population \bigg(1 + \dfrac{R}{100} \bigg) ^T

Solution:

Using the formula,

\sf \Rightarrow Total \: Population = Present \: Population \bigg(1 + \dfrac{R}{100} \bigg) ^T

Substitute the values,

\sf \Rightarrow Total \: Population = 15000 \bigg(1 + \dfrac{4}{100} \bigg) ^1

Solve the brackets,

\sf \Rightarrow Total \: Population = 15000 \times \dfrac{104}{100}

Cancel the zeros,

\sf \Rightarrow Total \: Population = 150 \times 104

Multiply 150 by 104,

\sf \Rightarrow Total \: Population = 15600

∴ Thus, the present population of a town is 15600.

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