the present population of a town is 15000 if the population increases at the rate of 4% per year then population after 2 years will be
Answers
Answer:
16224
Step-by-step explanation:
we can solve this in two ways one is the simple intrest type of way
1.we know that
SI=(p*r*t)/100
over here we can take p as 15000 rate as 4% and time as 1 year in the case of the 1st year
putting the values we get
Population increase(1st year )= (15000*4*1)/100=600
so the population at the end of year 1 is 15000+600=15600
now this will be the principal or the initial population of the 2nd year
Using the same formula we get
Population increase(2nd year)=(15600*4*1)/100 = 624
[here also the time will be only 1 year]
so the population at the end of the 2nd year is 15600+624=16224
hence your answer is 16224
2.the other way is using the compound intrest formula
ie Amount= p*[1+r/100]ⁿ where n is the time
putting the values we get
amount = 15000*[1+4/100]²
amount = 15000*[104/100]²
amount = 15000*[26/25]²
amount = 15000*26/25*26/25=16224
Answer:
16224
Step-by-step explanation:
given in the picture