Question

the present population of a town is 15000 if the population increases at the rate of 4% per year then population after 2 years will be​

Answer 1

Answer:

16224

Step-by-step explanation:

we can solve this in two ways one is the simple intrest type of way

1.we know that

SI=(p*r*t)/100

over here we can take p as 15000    rate as 4% and time as 1 year in the case of the 1st year

putting the values we get

     Population increase(1st year )= (15000*4*1)/100=600

so the population at the end of year 1 is 15000+600=15600

now this will be the principal or the initial population of the 2nd year

Using the same formula we get

Population increase(2nd year)=(15600*4*1)/100 = 624  

[here also the time will be only 1 year]

so the population at the end of the 2nd year  is 15600+624=16224

hence your answer is 16224

2.the other way is using the compound intrest formula

ie  Amount= p*[1+r/100]ⁿ  where n is the time

putting the values we get

 amount = 15000*[1+4/100]²

  amount = 15000*[104/100]²

amount = 15000*[26/25]²

amount = 15000*26/25*26/25=16224

 

Answer 2

Answer:

16224

Step-by-step explanation:

given in the picture