Math, asked by alfaiz32, 1 year ago

The present population of a town is 176400. If it increases at the rate of 5% p. a. ,what will be its population after 2 years?

Answers

Answered by SnehalD
4

Present population = 176400 , inc rate p.a = 5% ( 5% of current pop.)


First year,5% of 176400= 5/100*576400=28820


So,inc pop. = old pop + inc = 176400+ 28820 = 205220


Second year, 5 % of 205220 = 5/100*205220= 10261


So,inc pop = old pop + inc = 205220+10261=215481


Hence,pop. after 2 years = 215481 (ans)


alfaiz32: nhi bahi ye nhi hai
Answered by vikasoysw2a
1

Present population = 176400 , inc rate p.a = 5% ( 5% of current pop.)



First year,5% of 176400= 5/100*576400=28820



So,inc pop. = old pop + inc = 176400+ 28820 = 205220



Second year, 5 % of 205220 = 5/100*205220= 10261



So,inc pop = old pop + inc = 205220+10261=215481



Hence,pop. after 2 years = 215481 (ans)

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