Math, asked by nadafrehan1234, 9 months ago

The present population of a town is 176400 if the rate of growth in its population is 5% per annum find its population one year ago

Answers

Answered by Anonymous
26

Answer:

Population = 176400

rate = 5 %

Time = 1 year ago

a = p(1 +  \frac{r}{100}) - n

 = 176400 {(1 +  \frac{5}{100} })^{ - 1}

 = 176400 ({ \frac{21}{20} })^{ - 1}

 = 176400 \times \frac{20}{21}

 = 168000

hope it will be helpful ✌️

Answered by sanketsarve
4

Answer:

p=176400

R=5%p.a

T=1year

A=p(1+r/100)to the power n

A=176400(1-5/100)^1

A=167580

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