Question

the present population of a town is 200000.Its population increases by 10% in the first year and 15% in second year .Find the population of the town at the end of two year

Answer 1

Answer:

Population at the end of the two years is 253000 .

Step-by-step explanation:

As given

The present population of a town is 200000.

Its population increases by 10% in the first year .

10% is written in the decimal form

$= \frac{10}{100}$

= 0.10

Population increases by 10% = 0.10 × Present population

                                                = 0.10 × 200000

                                                = 20000

Thus

Popluation in the first year = Present population + Population increases by 10% .

                                                                  = 200000 + 20000

                                                                  = 220000

Thus the population in the first year = 220000

As 15% is written in the decimal form

$= \frac{15}{100}$

= 0.15

increases in population by 15% = 0.15 × Population in the first year

                                                    = 0.15 ×  220000

                                                    = 33000

thus

Population in the second year = Population in the first year + increases in population by 15% .

                                                   = 220000 + 33000

                                                   = 253000

Therefore the population at the end of the two years is 253000 .

               

Answer 2

Answer:

2,53,000

Step-by-step explanation:

Given : P=2,00,000

Population after first year  

=2,00,000(1+  

100

10

​  

)  

1

 

=2,00,000(  

100

110

​  

)=2,20,000

Principal for the second year =2,20,000

Population at the end of second year  

=2,20,000[1+  

100

15

​  

]  

1

 

=2,20,000×  

100

115

​  

 

=2,53,000