Math, asked by ayushisingh17, 1 year ago

the present population of a town is 24000. if it increases @ of 5% per annum what what will be its population after 2 years​

Answers

Answered by siddhartharao77
11

Answer:

26460

Step-by-step explanation:

Given, P = 24000, R = 5%, n = 2 years.

A = P(1 + r/100)ⁿ

   = 24000(1 + 5/100)²

   = 24000(105/100)²

 

   = 24000 * (105/100) * (105/100)

  = 24000 * 21/20 * 21/20

  = 26460.

Therefore, Population after 2 years = 26460.

Hope it helps!


Topperworm: Wonderful answer dear
siddhartharao77: Thank you dear!
Answered by Siddharta7
0

1st year

24000*5/100

Two zero cancel

240*5

=1400

1 year increase 1400 people

2years=1400*2=2800

24000+2800=26800

Therefore population of town after two years will be 26800

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