Question

The present population of a town is 36000.Find its population after two years if the rate of the growth of is population is 5percent per annum

Answer 1

Population after 2 yrs=

36000(1+5/100)^2

=36000(100+5÷100)^2

=36000(105/100)^2

=36000×105/100×105/100=36,690

{Ans}

Answer 2

Answer:

Here , P = 36000 , R = 5 % , T = 2 years , A = x

We know , A = p ( 1 + r/ 100) ^ n

A = 36000 ( 1 + 5/100 ) ²

A = 36000 ( 100 + 5 / 100 ) ²

A = 36000 ( 105/ 100 ) ²

A = 36000 × 105/100 × 105/100

A = 39,690