the present population of a town is 364500 if the population increase at the rate of 8% every year, what was the population 2 year ago
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Given :
- The present population of a town is 364500.
- The population increase at the rate of 8% every year.
To find :
- The population 2 years ago =?
Step-by-step explanation :
As We know that,
Present Population (P) = 364500
Rate (r) = 8%
Time (n) = 2 years
The population after "n" years,
P(1 - r/100)^n
•°• The population after two years,
= 364500(1 - 8/100)²
= 364500 × 92/100 × 92/100
= 364500 × 0.92 × 0.92
= 308512
Therefore, The population was two years ago = 308,512.
Answered by
0
Answer:
Two years ago the population is 308512.
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