Question

The present population of a town is 48000. It is increasing at the rate of 5% every year. What will be the increase in population in next 3 years?

Answer 1

given present population of town= 48000

increasing rate =5% every year

time = 3 years

so ,

48000×105×3/100= 151200

after 3 years population will be 151200

hope it help you

Answer 2

Answer:

The increase in population in next 3 years is 55566 .

Step-by-step explanation:

As the increase exponential function is given by

$y = a (1 + r)^{t}$

Where a is the initial value , r is the rate of interest in the decimal form and t is the time in years .

As given

The present population of a town is 48000. It is increasing at the rate of 5% every year for 3 years.

a = 48000

5% is written in the decimal form

$= \frac{5}{100}$

= 0.05

r = 0.05

t = 3 years

Put all the values in the formula

$y =48000(1 +0.05)^{3}$

$y =48000(1.05)^{3}$

$y =48000\times 1.15763$

y = 55566 (Approx)

Therefore the increase in population in next 3 years is  55566 .