Math, asked by santhosavallisenthil, 6 months ago

The present population of a town is 75,000. The population increases by 10% in the first year and decreases by 10% in the second year. Find the population after 2 years.​

Answers

Answered by ramessh149
1

Answer:

75000.

Step-by-step explanation:

10%-(-10%)=0% so it is 75000 the same

Answered by 57dhrutipatil
0

Answer:

The population increases by 10 percent is the first year and decreases by 10% in the second year. Find the population after 2 years. Solution: Here, initial population P = 75,000, population increase for the first year = r1% = 10% and decrease for the second year = r2% = 10%.

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