Math, asked by namanbathija06, 5 months ago

The present population of a town is 75,000. The population increases by 10% in the first year and decreases by 10% in the second year. Find the population after 2 years. plzzzz ans fast

Answers

Answered by Anonymous
0

Answer:

Step-by-step explanation:

A + B + AB/100

First two years, net increase.

10 + 10 + (10x10)/100 = 21%

Again,

Next two years, net decrease.

-10 -10 + 100/100 = -19%

Finally combined effect :

21 - 19 + (21 x -19)/100

= -1.99%

Net decrease after 4 years is 1.99%

Net population after 4 years is :

1,00,000 x 98.01% = 98010

Answered by manjeetkaurreddu
0

Answer:

75,000

Step-by-step explanation:

population in town =75,000

increase in first year = 10%

decreases in second year = 10%

population after 2 years =75000

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