Question

the present population of a village is 408. If it has increased at a rate of 4% every year. What was it's population 2 years ago​

Answer 1

Answer:

$population = 408 \: \: \: population \: after \: 2 \: years \: = 408 + \frac{4}{100} = 408.04 \: \: population \: after \: 2years \: = 408.04 + \frac{4}{100} = 408.08$

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Answer 2

Answer:

441.29

Step-by-step explanation:

it increases by 4% every year

For 1st year

(4×408) / 100 + 408 = 16.32 + 408 = 424.32

For 2nd Year

(4×424.32) / 100 + 424.32 = 16.97 + 424.32 = 441.29