Question

The present population of a village is 5408 . If it has increased at the rate of 4 percent every year what was its population 2 years ago

Answer 1

Answer:5848

Step-by-step explanation:

population after 1st year =

5408 + ( (4/100)*5408) = 5624

Population after 2nd year =

5624 + ( (4/100)*5624) = 5848.

Answer 2

Same question answered by me before. I will write that only.

Step-by-step explanation:

Solution :

Present population = (population 2 years ago) × (104/100)²

➡ 5408 = (population 2 years ago) × 26/25 × 26/25

➡ population 2 years ago = 5408 × 25/26 × 25/26 = 5000.

Hence :

Population 2 years ago is 5000.